Corrections to the Study Guide |
The words that you should change in your Study Guide are indicated in bold
1-12. 1/16 probability of a child like parent 1 (AaBbCcDd)
1-14. All the data are consistent with open being dominant.
1-17. b... The cross was PPSs x P-ss or P-Ss x Ppss.
1-23. b) Affected = Aa or AA
2-9. a) ...Progeny L2L4 will be spotted. There will be...
2-14. b) A homozygous rose gene would be Aabb
2-21. In the last line of the chart, the fraction should be 1/2 not 1/4.
2/23. Individual III-1 should have the IAi genotype. The second to last line should read: but III-2has the O phenotype.
2-28. d) Now II-3, II-4, III-6, III-7 in the Smiths family...and I-2, II-6, and II-7 in the Jeffersons family.
3-5. b) Parthenogenetic males from the Bb female would be...
3-8. b) 96 chromatids
3-15. ZZ: 1/2 x 1/3
3-17. yellow: 16+48=64 males
3-20. b) iv) II-6 therefore does not...
3-21. b) I-4 or II-9
3-23. The label on individual III-2 should be XCB Xcb
4-11. a)...four genotypic classes of offspring: CcBb, ccbb, Ccbb, and ccBb rabbits...
4-12. The allele designations should be cn+ instead of Cn and rd+ instead of Rd
4-15. ...in the parent a+b+c+ and a b c female flies...
4-17 b) 670 scute, echinus, crossveinless
4-19. second to last sentence of answer - the gene names are rv and rmp, not A and R
4-20. total tetrads = (3+(1/2)(27))/54
4-24. last sentence - ...there will be three phenotypic classes produced in the offspring
5-16. There are a) three origins b) six forks and c) the middle origin was activated later.